
Andy C. answered 08/17/18
Tutor
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Math/Physics Tutor
This was a challenging problem.
Volume = pi * radius^2 * height
v and r are the volume and radius of the small candle
V and R are the Volume and Radius of the larger candle
k is the consistent rate the candles burn per hour.
Then v = 4k and V=6k as given
4k = pi*r^2* H and 6k = pi*R^2*H with the heights the same
4k/(pi*r^2) = 6k/(pi*R^2)
4/r^2 = 6/R^2 <--- pi cancels; so does k
4/6 = r^2/R^2
2/3 = r^2/R^2
so the square of the radii of the candles (hence their volume, since pi and H are the same) are in 2 to 3 ratio
Hence, 2/3 = v/V <--- can multiply the 2/3 ratio by pi*H to get the volumes in the same proportion
v = (2/3)V <--- solves for v
So, it takes 2 hours to burn V - (2/3)V = (1/3)V
= (1/3)(6k)
= 2k
k=1 unit of volume per hour burns
(2/3)V - t*k = (1/2) [ v - t*k] where t is the time it takes for the smaller candle to be half the larger
(2/3)V - t = (1/2)[ v - t] <---- k=1 so it multiplies out
(2/3)V - t = (1/2)V - (1/2)t <--- distributive
(2/3)V - (1/2)V = t - (1/2)t <---- V on one side; t on the other
(1/6)V = (1/2)t <--- combines like terms
V = 3t <--- multiplies both sides by 6
6k = 3t <---- V=6k
6 = 3t <---- again, k=1
t=2
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ok... suppose the volumes are 10 and 15, as 10/15 = 2/3
The first burns off in 4 hours, so thats 10/4 = 5/2 = 2.5 units of volume per hour.
The other candle burns off in 6 hours, so 15/6 = 5/2 = 2.5 units of volume per hour.
in 2 hours, the first candle shall be 10 - 2*2.5 = 10 - 5 = 5
while the larger candle shall be 15 - 2.5*2 = 15 - 5 = 10 which is twice as large
This is a strategy on the SAT and ACT tests called "pick a number" to get the
answer quickly, but does not PROVE the result holds for ALL possible values.
Nevertheless, it supports the result found above.
Thanks for the challenging problem!