Not sure what you are asking, but, .1N NaOH is .1 M NaOH, because each NaOH has just one OH- in its formula. 1 N NaOH is, therefore, 1 M NaOH. So, depending on the acid you are titrating, which is to say, is it monoprotic (HCl) or diprotic (H2SO4) or triprotic (H3PO4), you will introduce a conversion factor that relates the normality of the base (1N) to the normality of the acid (1, 2, or 3 N)
If you are using .1N NaOH, you calculate the normality of the acid using the proper conversion factor, and you discover that the normality of the acid is, 1N, well then, if you had used 1 N NaOH, then you would have used one tenth as much volume for the titration, but the normality of the acid would be the same.
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