Mark M. answered 08/07/18
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫cos7xdx = ∫cos6x cosxdx
= ∫(cos2x)3cosxdx
= ∫(1-sin2x)3cosxdx
Let u = sinx Then du = cosxdx
= ∫(1-u2)3du = ∫(1 - 3u2 + 3u4 - u6)du
= u - u3 + (3/5)u5 - (1/7)u7 + C
= sinx - sin3x + (3/5)sin5x - (1/7)sin7x + C