find the measure of an angle whose supplement is 10 degrees more than twice its complement. let 90-x equal the degree measure of its complement and 180-x equal

Question

the degree measure of its supplement. how can i write and solve this equation.

Answer 1

Let the angle be x degrees

 

Its supplement = 180-x

 

Its compliment=90-x

 

The required equation is

 

180-x=2(90-x)+10

 

On solving the above equation

 

x =10 degrees