two coins are selected at random from a bag containing 3 dimes and 3 3 quarters. what is the probability that they are both quarters

Question

Probabilty 

Answer 1

Hi Emily,

 

There are 36 total coins in the bag.

 

P(quarter on first try) = 33/36

 

P(quarter on second try) = 32/35

 

P(2 quarters on first two tries) = (33/36)(32/35)  reduce

 

   =(11/12)(32/35)

 

 = 352/420 

 

 = 88/105

 

= approximately .838 or 83.8%