Anita A. answered • 06/30/18

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Community College Math Instr; TX Secondary Mathematics Certification

My combinatorial experience is rusty, but here is the way I'm tackling this question.

Total # of balls is 2n, but the number selected at each draw is 2 - 1B, 1W. So, there are n pairs, and the 'number selected' is 1.

Since

_{n }C_{r}=14,400, then_{14,400 }C_{1 }= 14,400, and n = 14,400. Total # balls is 28,800, but with the restriction that each pair has**1B and 1W**- I won't use 'number selected' as 2.Feeling a bit diffident and thinking it's too easy, please enlighten me.

Anita A.