two times the least of three consecutive odd integers exceeds three times the greatest by fifteen. what are the integers

Question

how do i write out this equation?

Answer 1

Let x be the first odd integer.

 

x + 2 will be the next odd integer and x + 4 will the 3rd odd integer.

 

2(x) = 3(x+4) + 15

 

Solve for x.

2x = 3x+12 + 15

2x = 3x + 27

-27 + 2x = 3x

-27 = 3x - 2x

-27 = x

 

So the first odd integer is -27

The second is -27 + 2 = -25.

The 3rd is -27 + 4 = -23.

 

Check:

2(-27) = 3(-23) + 15

-54 = -69 + 15

-54 = -54  True.

 

 

 

Answer 2

let the integers be (x-2), x and (x+2)

 

2(x-2) = 3(x+2) + 15

 

2x - 4 = 3x + 6 + 15

 

2x = 3x + 25

 

x = -25

 

The three odd integers are   -27, -25, -23