I hope you started by drawing a picture.
A rectangle has a length (l) and a width (w), and the rectangle's area is the length times the width (l*w)
In this case, we don't know the width, so I'll just continue using w for the width. We know that the length is 22 units more than the width, so the length is really w+22.
Instead of the area being l*w, I can write it as (w+22)*w. Make sure to use parentheses when you do this! We also know that the area is equal to 80 units2, so we have the equation (w+22)*w=80
Ok first, let's distribute on the left side: w2+22w=80
and subtract 80: w2+22w-80=0
This quadratic equation doesn't factor, so we can use the quadratic formula to solve from here - substitute a=1, b=22, and c=-80 into the formula w=(-b±sqrt(b2-4ac))/2a. Remember to disregard the negative root, since our width will not be a negative number!