The sum of deviations of a set of values x1,x2,x3,.,xN, measured from 50 is-10 and the sum of deviations of the values from 46 is 70 . Find the val.

Question

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Answer 1

I think your question is "find the value of N."

 

∑(x-50) = -10

∑(x-46) = 70

 

∑x - 50N = -10

∑x - 46N = 70

-4N = -80 after subtracting (see above)

Therefore N = 20