Pradip M. answered • 06/06/18

Tutor

4.8
(15)
Increase your Thinking & Knowledege Quotient (TKQ)

Hello Pragyan,

How I wish that I could draw a diagram!

If one follows the convention that 'REAL is +' and Virtual is '-'. This is easy.

For the convex lens u = 22.5 cm, f = 15 cm and this gives us v = 45 cm. Thus there is a real Image - which means converging rays.

Converging rays Indicate Virtual Object for the concave (diverging) lens at 45-15 = 30 cm.

For this lens u = -30 cm (virtual object) , f = -30 (focus is virtual) and thus v = ∞.

Or Diverging rays from the real object pass thru the first lens to converge at a point 30 cm on the other side of the diverging lens.

However due to the action of the 2nd lens these rays are rendered parallel and come right back (re-trace their path) after reflection from the plane mirror and so we get an image right at the point where the object is in the first place.

Note the distance of the plane mirror from the diverging lens is not material to the solution.

Hope this helps.

Let me know if you need further help.

Pradip

Pragyan S.

hey, I've no problem with my previous comment. please discard that. however, i have another question: does the image of the object is of reduced height, here?

Report

06/09/18

Pradip M.

Hello Pragyan,

The rays incident on the plane mirror are parallel to the axis and so they will retrace their path all the way. The Image will be formed (real) where the Object is . It will be upright and of the same size.

Pradip

Report

06/09/18

Pragyan S.

06/06/18