Maths help please

Question

no1. what is 5³

no2. what is (5⁴)³

no3. what is (-31)⁰

 

no.4. what is 4_^x + 4y-5a= ?  Evaluate given x=3,y=6 and a=-2(evaluate calls for plugging in the values and stating the final answer)

 

no5. find the product: (x + 3y) _* (x-8y)

 

no.6. factor x² + 3x +2

no.7. factor 3x²  + 7x + 2

no 8. factor x² - 21x - 72

no.9  Add (3x² - x + 7) + (6x² - 2) =

no 10. subtract (7a⁴ + 4a -7) - (4a⁴ + 3a -5)=

no 11. Divide: 3p+7/3 divided by 4^z/y

no 12. 4^-3=

no 13. 16^3/4 =

no 14.  square 2 . square 72 =

Answer 1

Here are a few for you. Try the rest.

 

1) 5³=5*5*5=125

2) (5⁴)³=(5)^4x3=5¹²=5*5*5*5*5*5*5*5*5*5*5*5= ? (I would leave it as 5¹²)

3) anything raised to the 0 power is 1. (except 0 raised to the 0 power which is undefined)

4) 4(3)+4(6)-5(-2)= ?

5)  use the FOIL method

8) x²-21x-72=(x   )(x   )   you finish it using 72=3*24

10) 7a⁴+4a-7-(4a⁴+3a-5)=7a⁴+4a-7-4a⁴-3a+5= ? (combine similar terms and be careful of the + and- signs)

13) 16^(3/4)=(16³)^1/4=(16*16*16)^1/4=(4096)^1/4=the fourth root of 4096; in other words find n such that n⁴=4096

hint:take the square root of 4096 to help you find n