Integration of 1- cot2 x

sin2x + cos2x = 1 Divide by sin2x to get 1 + cot2x = csc2x Replace cot2x in the given integral ∫1-(csc2x-1) dx ∫2 - csc2x dx = 2x + cot(x) + C

Integration of 1 minus cot Square x

Dom V. answered • 08/22/18

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sin²x + cos²x = 1

Divide by sin²x to get

1 + cot²x = csc²x

Replace cot²x in the given integral

∫1-(csc²x-1) dx

∫2 - csc²x dx = 2x + cot(x) + C

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Integration of 1 minus cot Square x

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Integration of 1 minus cot Square x

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

Why is the derivative of the answer to an integral equal to the primary function which we want to take integral of? I'm looking for the concept.

Integration

I need help on integration problems

int(sec(x)+tan(x))dx

How do you find the equation to an integral when the equation is not given but the answer to the integral is?

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