Charles K. answered 05/19/18
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Let: x = 2 and y = 1
Then,
x – y > 0
2 – 1 > 0
1 > 0 True
y – x < 0
1 – 2 < 0
–1 < 0 True
x + y > 0
2 + 1 > 0
3 > 0 True
Now let’s use some negative numbers. We always want to check all possibilities including zero, if there is no restriction. This includes fractions when appropriate.
Let: x = –1 and y = –2
x – y > 0
–1 – (–2) > 0
1 > 0 True
y – x < 0
(–2) – (–1) < 0
–1 < 0 True
x + y > 0
–1 + (–2) > 0
–3 > 0 False
Therefore, answer choice E is correct.