The are of a rectangular is 55 yd^2, and the length of the rectangle isis 4 yd less than three times the width. Find the dimensions of the rectangle .

Question

Please include the length and the width in the answer thank you

Answer 1

Let's use ALGEBRA!!

 

LW = 55   ('AREA' EQUATION)

L = 3W - 4 (relationship between length & width)

 

Use substitution, now, to solve for W, etc.

 

This kind of work is what your textbook and your teacher are trying to impart to you.  STUDY!

Answer 2

LW = 55

 

L = 3W - 4

 

(3W -4)W = 55

 

3W² - 4W - 55 = 0 

 

If you can factor it, do so; otherwise use the quadratic formula, to get W = 5 and L = 11

Answer 3

Let w = width of the rectangle, then l = 3w-4

 

Area = l x w

 

55 = (3w-4)(w)

 

55 = 3w² -4w

 

0 = 3w² - 4w - 55

 

0 = (3w + 11)(w - 5)

 

w = 5 or -11/3 (the width cannot be a negative number)

 

so w=5, l = 11