Arthur D. answered 04/15/18
Tutor
4.9
(283)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
let ab be the number
10a+b=3(a+b)
b=3a+1
10a+b=3a+3b
10a-3a=3b-b
7a=2b
b=3a+1
substitute
7a=2(3a+1)
7a=6a+2
7a-6a=2
a=2
b=3*2+1
b=7
the number is 27