Write the equation of the circle

Question

circle B that passes through (3,6) and has center B(-2,6)

Answer 1

To start, remember the basic equation of a circle: (x-h)² + (y-k)²= r.²

 

The coordinate (h,k) is the center of the circle.

 

So, the basic circle equation becomes: (x-(-2))² + (y-6)²= r² or (x+2)² + (y-6)²= r²

 

So, next we can plug in the point it passes through:

 

(3+2)²+ (6-6)2= r²

(5)² + (0)² = r²

(5)²= r²

√(5)² = √r²

5= r

 

The final answer would be (x+2)² + (y-6)²= 25