
Andrew M. answered 04/11/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
In order to enclose the greatest area you want the overall rectangle to be a square.
Draw a square with side length x
Inside this square put 6 parallel lines, either horizontal or vertical...
Each of those lines will also be length x.
Thus we end up with 10 lines of length x.
These sum to 2400 ft
10x = 2400
x = 240 ft
The area enclosed overall is x2
2402 = 57,600 ft2 of enclosed corral.