log3(x+4) = 1 - log3(x+2)
Since the sum of logarithms is the log of the product
log3[(x+4)(x+2)] = 1
use each side as the exponent of 3
(x+4)(x+3) = 3
x2 + 6x + 8 = 3
x2 + 6x +5 = 0
(x+1)(x+5) = 0
x = -1 and x =-5 are the roots
You should go back and verify that each of the roots satisfies the original equation!