f(x) = 2x3 - x2 + 2x - 3
f(0) = 2·03 - 02 + 2·0 - 3 = -3
f(2) = 2·22 - 22 + 2·2 - 3 = 5
The intermediate value theorem states that the function f(x) on the interval [0, 2] will take on all values between f(0) and f(2) at least once. Since 0 is between -3 and 5, there must be an x between x=0 and x=2 where f(x) = 0. So yes, there is at least one real zero between x=0 and x=2.

Kenneth S.
04/05/18