
Philip P. answered 09/15/14
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I assume you mean, "how do you solve x2 + 2x + 16 = 0"?
You solve it by factoring or using the quadratic formula. In this case, the equation does not factor, so use the quadratic formula:
x = [-b ± √(b2-4ac)]/2a
Where:
a = the coefficient of the x2 term = 1
b = the coefficient of the x term = 2
c = the constant term = 16
x = [-2 ± √(22-4*16*1)]/2
x = [-2 ± √(-60)]/2
x = -1 ± i√15
Since we have the square root of a negative number, the roots are complex numbers (no real roots).