Kenneth S. answered • 03/27/18
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Algebra II EXPERT will help you survive & prosper
A function for area total is needed: f(x) = pi(x^2) + (40-x)^2
This is a quadratic f(x) and its graph is a parabola; the minimum occurs at the vertex, where x = -b/(2a).
All you have to do is determine what a and b are, by simplifying f(x).
Kenneth S.
I erred. If x is the length of the circle (circumference), then the radius should be x/(2pi) and the associated area is pi times the square of this radius value.
Then 40-s, the remainder, must be divided by four, and THAT value must be squared to compute the square's area.
The f(x) should be revised accordingly. The other paragraphs are correct.
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03/27/18
Ashley D.
I don't this is the right work for my problem but thank you!
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03/28/18
Ashley D.
03/27/18