What is the solution set for 2x^2+20=8 ?

Question

A. negative square root of 6

B. Square root of 6, and A^

C. negative i outside of the square root of 6

D. i outside of the square root of 6 and C

Answer 1

2x² + 20 = 8

2x² = -12

x² = -6

x = ±i√6