Andrew M. answered 03/25/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
f(x)=x3- x2- 4x + 4
The possible real roots are the factors of the constant, 4, divided by the factors
of the coefficient of the highest powered variable, 1
Possible real roots: ±{1, 2, 4} which gives us 6 possibilities.
Total number of roots is 3
Factor x2 from 1st two terms and -4 from last 2 terms
f(x) = x2(x-1) - 4(x-1)
f(x) = (x2-4)(x-1)
Note that x2-4 is difference of two squares... (x2-22)
a2 - b2 = (a-b)(a+b)
f(x) = (x-2)(x+2)(x-1)
The roots are {2, -2, 1}
Andrew M.
03/25/18