A cruise left port A and traveled towards port B 225 km away. After 1.5 hours of travel, the cruise was stopped for a half an hour and then it had to increase i

Question

A cruise left port A and traveled towards port B 225 km away. After 1.5 hours of travel, the cruise was stopped for a half an hour and then it had to increase its speed by 10 km/hour in order to reach port B on time. Find the original speed of the cruise.

Answer 1

There is not enough information to solve this problem.

V is the original velocity in kilometers per hour....

It travels for 1.5 hours at that speed, so it went 1.5V km

It then traveled the remaining 225-1.5V at speed of V+10

Let T be the total time....

then T = 1.5 + (225-1.5V)/(V+10) + 1/2 <--- time at slower speed is 1.5 hours;

time at faster speed is the fractional expression

PLUS the half hour of time LOST when they stopped

If you know the total time, you can then find V by solving the

last equation...

otherwise we need to know the distance traveled in either portion

of the cruise...