11 puppies = 5 poodles + 3 terriers + 3 retrievers
P(Rebecka selects a poodle) = 5/11
P(Aaron selects a poodle) = 5/11
P(both select a poodle) = (5/11)*(5/11) = 25/121 ≈ 0.2066
The probability of both Rebecka and Aaron select a poodle is about 0.2066. Keep in mind that these events are independent because the first event didn't affect the second event. In terms of replacement, the first time the poodle was selected the store replaced with the same breed of the puppy for the next customer to come choose their puppy. The sample size will not be affected in future events.