Mark M. answered 03/05/18
Tutor
4.9
(954)
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫[5/(10t2 + 90)dt = (1/2)∫[1/(t2 + 9)]dt
= (1/2)∫[1/(t2+32)]dt
= (1/2)(1/3)Arctan(t/3) + C
= (1/6)Arctan(t/3) + C