
Andrew M. answered 02/18/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Volume of a right circular cylinder: πr2h
r = d/2 = 1.5 inches
h = 5 inches
Cost = (πr2h)k where k is the constant of proportion
1.60 = π(1.5)2(5)k
k = 1.6/[π(1.5)2(5)] = 0.045271
So the formula is: Cost = 0.045271(πr2h)
For 5.5 inches high, and 3.25 inches diameter:
r = 1.625
Cost = π(1.625)2(5.5)(0.045271) = $2.07
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Weight: Cost = kw where w is weight and k is constant of proprotionality
1.6 = 16k
k = 1.6/16
k = 0.1
Cost = 0.1w
c = 0.1(26) = $2.60

Michael P.
02/20/18