Raymond B. answered 01/01/21
Math, microeconomics or criminal justice
quantity demanded, x, = 25-20p, as p goes up, quantity demanded goes down
or you can solve that equation for p to get
p=(25-x)/20
revenue is price times quantity demanded or
R= px
R(x) = x(25-x)/20 = (25x -x^2)/20 = 5x/4 - x^2/20
or if you want R(p), revenue in terms of price
R=px
R(p)= p(25-20p) = 25p -20p^2
doing it this way allow you to solve for the revenue maximizing price by taking the derivative and set =0
R'(p) = 25 - 40p
40p = 25
p = 25/40 = 5/8 = 0.625