Kenneth S. answered 02/12/18
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
I would solve this by making a probability tree. Stage 1 has three branches labeled T,C,L and the individual probabilities associated with these are 10/22, 5/22, 7/22, respectively.
From the end of each of these three limbs, construct 3 limbs for Stage 2, labeled CTL, respectively.
Choose the node associated with T (stage 1) and C (stage 2). The prob of C at stage 2 is 5/21 and so this TC path has probability (10/22)(5/21).
But there's one other way to satisfy the event, namely the path where C is stage 1, T is stage 2; this probability is (5/22)(10/21).
Each probability cited above (TC and CT) has value 25/(11•21) so the P(one choc, one toffee) is twice this value.
You can compute this in decimal, yourself.