Bobosharif S. answered 02/12/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
(x^2-ax^2+(a+1)x-2)/(x-a)=(1-a)x+(1+2a-a^2)-(a^3-2a^2-a+2).
Therfore, to be divisible by x-a
a^3-2a^2-a+2=0
from which follws that a can be -1, 1 and 2.
a^3-2a^2-a+2=0
(a-2)(a^2-1)=0