
Bobosharif S. answered 02/07/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
x2 + y2 ≤ 9 and y ≥ |x|.
To visualize the area, I suggest to draw x2 + y2 = 9 and y = |x|.
This is basically the area of the sector bounded by y=-x and y=x (from bottom) and x2 + y2 = 9 (from top).
Area of Sector = θ /2* r2 (here θ =π/2. I think you guess why)
So the area is (9/4)π. This is actually 1/4 of area of the circle x2+y2=9.