Ayoninu S.

asked • 02/04/18

Maths Challenge

 A strange announcement was made on the radio about a local election with three candidates: Mrs Allan, Mr Baxter and Ms Campbell. "Mrs Allan beat Mr Baxter by 1/8 of the total votes cast. Mr Baxter beat Ms Campbell by 1/7 of the total votes cast. The votes cast for Mrs Allan was 350 fewer than 3 times Ms Campbell's votes." How many votes did each candidate get? Can I please get some help with this ASAP?

1 Expert Answer

By:

John M. answered • 02/04/18

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Ayoninu S.

Hey nit meaning to pester you but could you show me how youve done thr substituiton?
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02/05/18

John M.

  1. take a look at the four equations and come up with a strategy.  One approach, that I will use here, is to initially put everything in terms of the variable C and then substitute that into Eqn 1.  Then, C will be expressed in terms of T.  Then you will be able to express both A and B in terms of T (using Eqn 2 and 3).  Finally, use Eqn 4 to find a value for T.
  2. Rewrite Eqn 1 so that A is expressed in terms of C.  
    1. A = B + (1/8)T  {Eqn 2}
    2. Substitute Eqn 3 into Eqn 2
    3. A = C + (1/7)T + (1/8)T = C + (15/56)T    {Eqn 5}
    4. Now we can substitute Eqns 2, 3 and 5 into Eqn 1.  Why?  Because we wanted to have variable C expressed in terms of T
    5. A + B + C = T {Eqn 1}
    6. C + (15/56)T + C + (1/7)T + C = T
    7. 3C + (23/56)T = T
    8. 3C =  T - (23/56)T =  (33/56)T
    9. C =  (33/56)T / 3
    10. C = (33/168)T     {Eqn 6}
    11. With Eqn 6, we now achieved the first goal of having the variable C expressed in terms of T.
    12. Now substitute Eqn 6 into Eqn 3 to get B expressed in terms of T
    13. B = C + (1/7)T   {Eqn 2}
    14. B = (33/168)T + (1/7)T  =  (57/168)T    {Eqn 7}
    15. Now substitute Eqn 7 into Eqn 2 to get A expressed in terms of T
    16. A = B + (1/8)T    {Eqn 2}
    17. A = (57/168)T + (1/8)T =  (78/168)T   {Eqn 8}
    18. Now we have all the variables A, B and C expressed in term of T.  If we've done everything correctly, when we sum A + B + C, it should equal 1T (because of Eqn 1).    So, just as a doublecheck: (78/168)T + (57/168)T + (33/168)T =  1T.  Everything checks out OK so far.
    19. Now, we use Eqn 4 to get a numerical answer.
    20. A = 3C - 350  {Eqn 4}
    21. Substitute the values of A and C, which are expressed in terms of T.  So, we will be substituting Eqns 6 and 8 into Eqn 4.
    22. (78/168)T = 3(33/168T) - 350
    23. (78/168)T = (99/168T) - 350
    24. (-21/168)T = -350
    25. T = -350(-168/21)  =  2800
    26. Now that you have the value of T, you should be able to find the values of C, B, and A by substituting T back into Eqns 6, 7 & 8.  I leave that to you.
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02/05/18

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