
Arturo O. answered 02/02/18
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(a)
t = years elapsed = 550
m(0) = initial amount = 300 g
m(t) = mass remaining after t years
m(t) = m(0) (1/2)t/250
m(t) = (300 g) (1/2)t/250
m(550) = (300 g) (1/2)550/250 ≅ 65.29 g
(b)
Set m(t) = 65 g and solve for t, with the initial amount reset to the result from part (a).
65 = 65.29 (1/2)t/250
t = 250 ln(65/65.29) / ln(0.5) ≅ 1.606 years