Find the equation of the line (in slope intercept form) passing through the point (-1,6) and perpendicular to the line passing through the origin with slope .5.

Question

I need help how do i figure this out

Answer 1

The product of slopes of perpendicular lines is -1, so the slope of the perpendicular line is

m = -1/0.5 = -2

y = -2x + b

Find b from the given point.

6 = -2(-1) + b

b = 4

y = -2x + 4