The idea here is probably that 3i and 2 -i are zeros of the desired polynomial. Since the coefficients are rational, the complex zeros come in complex conjugate pairs. This means that -3i and 2+ i are also zeros. A start on the polynomial is to write
P(x) = (x - 3i) (x + 3i) (x -(2-i) )( x - (2 +i))
Multiplying this all out results in
P(x) = x4 + 14 x2 + 45
Since the coefficient of the leading term is 1, this is the final answer.