A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory.

Question

In how many seconds after the shot will cannonball be at the highest point?

 

In _____________ seconds cannonball will be at the highest point. The highest point is ___________.

 

PLease tell me the answer!!!!!

Answer 1

the graph is a parabola, opening downwardly, so the maximum y occurs at the vertex.

therefore t = -b/(2a) will allow you to calculate the t value of that maximum height.

(b = 300, a = -16)

 

once you have that t value, the max. height is y(t)