Find three consecutive integers such that the sum of the first and third is 40

Question

Please help me I'm horrible at math and I need this done by three days HALP

Answer 1

x = first integer

x + 1 = second integer

x + 2 = third integer

 

so:

x + x + 1 + x + 2 = 40 + x + 1

3x + 3 = x + 41

2x = 38

x = 19

 

thus:

first integer = 19

second integer = 20

third integer = 21

 

19 + 21 = 40