What was her average speed that day?

Question

On Wednesday,she ran for 1 1/5 hours and traveled 6 2/5miles.

Answer 1

Hi Mia,

 

Thanks for sharing your question. 

 

For this problem, we will need to:

 

1. Convert our mixed numbers to improper fractions

2. Use the distance, rate, and time formula to solve the speed. 

 

1. Covert Mixed Numbers into Improper Fractions.

The math becomes easier whenever you use improper fractions. 

 

In our case, our friend ran for a time of 1 and 1/5 hrs. If we convert it to an improper fraction we have:

 

T = 5/6 hrs

 

We can apply the same idea to the distance she traveled. If we convert 6 and 2/5 miles to an improper fraction, we have:

 

D = 32/5 miles

 

2. Use the Distance, Rate, and Time Formula to Solve for Speed.

 

Recall, that the formula is:

 

D = R * T

 

where,

 

D = the distance traveled.

R = the Speed.

T = the time.

 

If we substitute our numbers into the equation, we have:

 

( 32/5 mi ) = R * ( 5/6 hrs )

 

From here, we need to solve for R. 

 

If we divide 5/6 hrs on both sides, our answer becomes:

 

192/25 miles per hour = R

 

Be sure to convert your answer into a mixed number. 

 

If you have any troubles following the steps above, please login in for a session. 

 

Thanks for using Answers,

 

Have a great day!