Y=4\3x-1 crosses perpendicular

Question

It has crosses perpendicular

Answer 1

I assume you meant to say that you have the equation of a line given by

 

y = (4/3)x - 1

 

and that you seek the equation of a line that is perpendicular to the given line.  When 2 lines are perpendicular, the product of their slopes is -1.  Therefore, the slope of the perpendicular line must be

 

m = -1/(4/3) = -3/4

 

Then any line of equation

 

y = (-3/4)x + b,

 

where b is any real number, is perpendicular to the given line.