Write an equation for a line perpendicular to y = -3 x -5

Question

Write an equation for a line perpendicular to y = -3 x -5 and passing through the point (6,6)

Answer 1

A line perpendicular to a given line will have a slope that is the negative reciprocal of the slope of the given line. Since our slope is -3, the slope of our perpendicular line would be 1/3.

We plug the slope and the given point into the Point-Slope formula

(y - y1) = m (x - x1)

(y - 6) = 1/3 (x - 6)

Simplify that equation and you'll have the equation of the line