Bobosharif S. answered • 12/28/17
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3a^2=6a+9 a=?
a^2-2a-3=0
(a-3)(a+1)=0
a=3.
Answer a.3
Bobosharif S.
It says ".. exceeds six times the number by nine". So a^2 exceeds 6a+9. Actually it should be a^2>6a+9 (greater but not equal)
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09/29/20
Spencer K.
Can you explain why you added 9 rather than multiplying by 9 please? The answer I find is E) none. However the answer sheet finds the same solution as you do. In all the training I have had in previous courses the term "by" is a term utilized for multiplication. As such, the initial formula would be: 3a^2 = 6*a*9 Please advise.09/29/20