
Andy C. answered 12/19/17
Tutor
4.9
(27)
Math/Physics Tutor
THere are many choices.
For example, we can put the endpoint of the mouth
at (-3,-3) and (3,-3) and it bellies down at (0,-6), the vertex
So
(-3,-3) (3,-3) (0,-6) <--- vertex
Vertex form is:
y = k(x-k)^2 + k with (h,k) = (0, -6)
(-3,-3) (3,-3) (0,-6) <--- vertex
Vertex form is:
y = k(x-k)^2 + k with (h,k) = (0, -6)
The equation becomes:
y = k x^2 + -6 = kx^2 - 6
For x=-3 or x = 3, x^2 = 9
y = k x^2 + -6 = kx^2 - 6
For x=-3 or x = 3, x^2 = 9
Plugging these points into the vertex equation:
-3 = k(9) - 6
3 = 9k
k = 1/3
The equation for the mouth of the parabola is:
y = (1/3)x^2 - 6
y = (1/3)x^2 - 6
with
Domain X = [-3,3]
Domain X = [-3,3]