solve for x in the equation y = log base 12 x

The logarithm expresses te power that the base needs to be elevated to get a number:

y = log12(x)

x= 12

^{y}-
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solve for x in the equation y = log base 12 x

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The logarithm expresses te power that the base needs to be elevated to get a number:

y = log12(x)

x= 12^{y}

y = log_{12}(x)

12^{y} = 12^{log12(x)} [Identity: a^{loga(x)} = x]

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