math help please

Question

2/3_x - 4=2

                       number two question.

8(_x-2)+3-3(_x-4)=3

                        number three question

-1.2-3_x=0.6_x +6

                        number four question

10(a+3)=9[a-(1-a)]

                         number five question

2/3(4_x-9)=3-2_x-3/6

                         number six question

solve for x. a_x+ b_y=c_x + d

                                         thanks in advance

Answer 1

2/3(x)-4=2

2/3(x)=6

(3/2)(2/3)x=(3/2)*6

x=9

 

8(x-2)+3-3(x-4)=3

8x-16+3-3x+12=3

5x-1=3

5x=4

x=4/5

 

-1.2-3x=0.6x+6

-3x=1.2+0.6x+6

-3x=7.2+0.6x

-3x-0.6x=7.2

-3.6x=7.2

-36x=72

x=72/(-36)

x=-2

 

10(a+3)=9[a-(1-a)]

10a+30=9[a-1+a]

10a+30=9[2a-1]

10a+30=18a-9

30=-10a+18a-9

30=8a-9

30+9=8a

39=8a

a=39/8=4 7/8

 

(2/3)(4x-9)=3-2x-3/6

(8/3)x-6=2 1/2-2x

(8/3)x+2x-6=2 1/2

(4 2/3)x=6+2 1/2

(14/3)x=17/2

(3/14)(14/3)x=(3/14)(17/2)

x=51/28 or 1 23/28

 

ax+by=cx+d

ax-cx=d-by

(a-c)x=d-by

x=(d-by)/(a-c)