
Chris M. answered 12/14/17
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The problem states that F=k/r2 where F is the gravitational force (same as the weight of the astronaut), r is the distance between the object and the center of the earth, and k is the constant of proportionality. We need to find k first to solve the problem.
We know the astronaut weights 209 pounds wen he/she is 4000 miles from the center of the earth (standing on the earth's surface).
So 209=k/(4000)2
Solving for k we have
k=209(4000)2
To find the weight of the astronaut at 4300 miles above the earth (or 4000+4300=8300 miles from the center of the earth) we plug this distance into the equation along with the determined value for k.
F=209(4000)2/(8300)2
F=48.5 pounds
So the astronaut weighs 48.5 pounds when 4300 miles above the earth's surface.
Note: astronauts in orbit "feel" weightless because this gravitational force is offset by the centripetal force of the orbit (like the outward force on a merry-go-round)
Good Luck
Cheers
-Chris