Need to simplify:

-x²y²

x½y0

I know that y0= 1 and x½ = √x

which leaves me with -x²y²

√x

x½y0

I know that y0= 1 and x½ = √x

which leaves me with -x²y²

√x

But then I am stuck.

Thanks for helping.

Need to simplify:

-x²y²

x½y0

I know that y0= 1 and x½ = √x

which leaves me with -x²y²

√x

x½y0

I know that y0= 1 and x½ = √x

which leaves me with -x²y²

√x

But then I am stuck.

Thanks for helping.

Tutors, please sign in to answer this question.

El Paso, TX

Hello John,

You are correct that y^{0} and that x^{1/2}=√x. However, in this type of problem, it is best not to convert to a square root at this step. Instead, beginning from this point:

(-x²y²)/(x½)

The rule is that if you are dividing a variable, we subtract the values for their exponents. This means that:

x^{2}/x^{1/2}

=x^{2-1/2}

=x^{3/2}

So we end up with the final answer of -x^{3/2}y^{2}

This form is generally considered the most simplified form, but if you want to express it with the square root, you can also call it:

-√(x^{3})y^{2}

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