Hello John,
You are correct that y^{0} and that x^{1/2}=√x. However, in this type of problem, it is best not to convert to a square root at this step. Instead, beginning from this point:
(-x²y²)/(x½)
The rule is that if you are dividing a variable, we subtract the values for their exponents. This means that:
x^{2}/x^{1/2}
=x^{2-1/2}
=x^{3/2}
So we end up with the final answer of -x^{3/2}y^{2}
This form is generally considered the most simplified form, but if you want to express it with the square root, you can also call it:
-√(x^{3})y^{2}
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