Xavier has $9.25 in dimes and quarters.If he has 75 coins,how many of each type of coin does he have

Question

need answer

 

Answer 1

 

D + Q = 75 --> Q = 75 - D

 

10D + 25Q = 925 <--- amounts are in pennies

 

10D + 25(75-D) = 925

 

10D + 1875 - 25D = 925

 

1875 - 15D = 925

 

 1875 - 925 = 15d

 

950 = 15 d

 

d = 950/15 = 63 and 1/3

 

Q = 75 - 63 and 1/3 = 11 and 2/3

 

CHECK:

 

  (11 and 2/3) * 25 = (63 and 1/3)*10 = 291 and 2/3 + 633 and 1/3 = 925

 

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The answer, as posted, is PROVEN to be correct.