Find the ratio of the width of a regulation size basketball court to its perimeter is it's 94 ft length by 50 ft width?

Question

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Answer 1

Court is 94 ft length by 50 ft width

P = 2(94+50) = 2(144) = 288 ft

 

Ratio of width to perimeter 50 to 288

50:288

50/288 = 25/144

25:144