
Andy C. answered 01/04/18
Tutor
4.9
(27)
Math/Physics Tutor
C is Child ticket price
A is Adult ticket price
S is Senior ticket price
6C + 4A = 59.50
2A + 3S = 35.90
A = 2C
Substitutes the third equation into the first equation:
6C + 4(2C) = 59.50
6C + 8C = 59.50
14C = 59.50
C = 59.50/14 = 4.25
Adult ticket is A= 2C = 2(4.25) = 8.50
Solving the second equation for S:
3S = 35.90 - 2A
S = (35.90 - 2A)/3 = (35.90 - 2(8.50))/3
= (35.90 - 17)/3
= 18.90/3
= 6.30
Senior tickets cost $6.30
Children tickets cost 4.25
Adult tickets cost 8.50
6*4.25 + 4 * 8.50 = 59.50
2*8.50 + 3 *6.30 = 35.90
THese answers check out, so with confidence
we can say
4*6.30 + 2*4.25 = 33.70
shall be the price for 4 senior and 2 children tickets