
Mark M. answered 12/02/17
Tutor
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(278)
Mathematics Teacher - NCLB Highly Qualified
a)
an = a1 + (n - 1)d
2009 = 1 + 2n - 2
2009 = -1 + 2n
2010 = 2n
1005 = n
S1005 = (1005/2)(1 + 2009)
Can you solve for S1005?
b) and c) done the same way
Paola R.
12/03/17